dave
01-15-2010, 09:01 AM
http://www.davetyner.com/forum/picture.php?albumid=1&pictureid=8
So, first to explain the THREE variables:
IR = Inside radius of the head
X = the distance from the vessel centerline out to where your nozzle is
Y = how far the inside of the head is from the bottom of the head. To this we will add the wall thickness of the head to get you the desired projection to your nozzle.
The formula is:
Y=IR/2 * √(1-X²/IR²)
(Where √ means “square root”)
So, lets say your nozzle is 2’ out from the centerline (X=24) and the ID of the vessel is 6’ (ID = 72 so IR = 36). To find Y we plug in the numbers:
Y = 36/2 * √(1-24²/36²) = 18 * √(1-0.444) = 18 * √0.555 = 13.42”
Finally, you add the wall thickness (let’s say 0.25”) gives us 13.67” projection from the tangent line to the start of the centerline of a nozzle that is 2’-0” offset from the vessel centerline. Usually, the nozzle will have a standard length to the face of flange that you can add to this number.
Thanks to JH for this!!
So, first to explain the THREE variables:
IR = Inside radius of the head
X = the distance from the vessel centerline out to where your nozzle is
Y = how far the inside of the head is from the bottom of the head. To this we will add the wall thickness of the head to get you the desired projection to your nozzle.
The formula is:
Y=IR/2 * √(1-X²/IR²)
(Where √ means “square root”)
So, lets say your nozzle is 2’ out from the centerline (X=24) and the ID of the vessel is 6’ (ID = 72 so IR = 36). To find Y we plug in the numbers:
Y = 36/2 * √(1-24²/36²) = 18 * √(1-0.444) = 18 * √0.555 = 13.42”
Finally, you add the wall thickness (let’s say 0.25”) gives us 13.67” projection from the tangent line to the start of the centerline of a nozzle that is 2’-0” offset from the vessel centerline. Usually, the nozzle will have a standard length to the face of flange that you can add to this number.
Thanks to JH for this!!